I'm surprised that you have a first year physics textbook. Since you do, try opening the
book to the chapter about conservation of momentum. Conservation of momentum is a very
important concept in physics that helps analyze collisions, because even though a lot of
complicated interactions take place in a collision, they all have to conserve momentum,
and momentum is conserved throughout the collision. See:
http://hyperphysics.phy-astr.gsu.edu/hbase/conser.htmlhttp://hyperphysics.phy-astr.gsu.edu/hbase/elacol.htmlWe need a bit of information about the mass of concrete slab
and the jet. From page 167 of the book "Nuclear Power in Canada and Beyond":
http://books.google.com/books?id=Eq_3A95k1u8C&pg=PA167&lpg=PA167&dq=sandia+phantom+jet+containment+mass&source=bl&ots=CXKYE8-r2T&sig=qL4L4D8ZMh8GilzTwo0q9J0KsS8&hl=en&ei=QfdWTbe_FpG6sQOqz7GcDA&sa=X&oi=book_result&ct=result&resnum=1&ved=0CBMQ6AEwAA#v=onepage&q=sandia%20phantom%20jet%20containment%20mass&f=falsewe see that the concrete block had a mass 25 times that of the jet
"From the mass ratio of the jet to concrete slab (1:25)..."
Momentum is conserved in the collision. Before the collision, all the momentum is in the jet.
After the collision, that momentum is shared between the pieces of jet and the block. However,
we can make an assumption that simplifies the arithmetic. Let the block get
all the momentum.
This will be an upper limit for the amount of momentum the block can get, and thus provide an upper
limit for its velocity. The true velocity will be somewhat less since momentum had to be shared with
the remnants of the jet.
Let mj = mass of the jet
mb = mass of the concrete block
vj = velocity of jet before collision
vb = velocity of block after collision
So assuming all the momentum was in the jet before the collision,
and all the momentum was in the block after the collision, we
can write the following equation.
(mj)*(vj) = (mb)*(vb)
or vb = (vj)*(mj)/(mb) = vj/25
The last result comes from using the ratio of the masses of jet and block.
>From the above book link, the mass of the block was 25X the mass of the jet.
Because of our assumption, vb is an upper limit on the velocity of the block.
We can now calculate the energy for the block. The kinetic energy of an object
is one-half the product of the mass and the square of the velocity. So the
energy of the block Eb is given by:
Eb = (1/2)(mb)(vb)2
We know that (mb)=25(mj) and (vb)=(vj)/25 so
Eb = (1/2)(25 mj)(vj/25)2 = (1/2)(mj)(vj)2 / 25
however (1/2)(mj)(vj)2 is the energy of the crashing jet, Ej
So Eb = Ej/25 = 4% of Ej
Recall this is a maximum, the block actually got
less than
4% of the jet's energy.
So only 4% of the jet's energy went into moving the block. The
remainder 96% of the energy was dissipated in doing damage.
This is exactly what is stated in the above book:
"...we know that 96% of the jet's kinetic energy went into the jet's destruction
and the penetration of the concrete, which the remaining 4% was dissipated in
accelerating the slab."
So the fact that the slab was not anchored makes only a
trivial 4% change
in the energy available to do damage.
The jet only penetrated 2.5 inches into the containment wall. The addition of
another 4% of the energy is not going to make the penetration increase several feet.
The book also explains that the fuselage of even a large wide-body jet is no match
for the containment wall. The only parts of the aircraft that
might have a chance
to breach the wall are the engines.
That was also the conclusion reached by the scientists and engineers at Sandia
National Labs who conducted the test. Therefore, they continued their test series
by slamming whole engines into containment walls.
Shortly after 9/11, the ASME, the American Society of Mechanical Engineers held a
briefing to instruct members of Congress and their staffs on the supposed threat
of terrorist-hijacked airliners to nuclear power plants:
http://www.asmenews.org/archives/backissues/jan02/features/nucbrief.htmlThe ASME briefing referred to these tests at Sandia:
"During the Sandia tests in 1997, a 4,000-pound jet engine slammed into a 24-inch-thick
concrete wall at 240 mph, resulting in extensive cracking and spallation — concrete pieces
on the inside of the wall become dislodged and airborne — but no penetration.
The same engine impacting a 63-inch-thick, reinforced concrete wall, similar to the exterior
of a nuclear containment structure, at 480 mph resulted in less damage and no penetration."
So the only part of an airliner that could be of concern, which were the engines, were shown
in a series of tests by Sandia National Laboratory that the jet engines
can not penetrate the
containment either, even at full airliner speeds.
Hence, the conclusion by the ASME as delivered to members of Congress:
Tests conducted by Sandia National Laboratories indicate that America's 103 nuclear power
plants provide a significant level of protection against terrorist attacks, experts said
last month during an ASME-sponsored briefing on Capitol Hill."
The anti-nukes have been
lying that these test are flawed. By claiming that the
block not being anchored invalidates the test, when a simple calculation doable by any
junior high school student that has had a physics class shows the effect of moving the
block to be a mere 4% in the available energy. When the anti-nukes insist otherwise, they
are just proving that they are ignorant of junior high school physics.
Sandia National Laboratory stands behind its tests. The ASME, the American Society of
Mechanical Engineers, the professional society for mechanical engineers endorses the tests.
It would appear that the containment wall alone would suffice for protection of the reactor
from airliners. However, the containment wall is just the first stage of the protection.
There are more barriers inside the containment. I refer to the following diagram:
In addition to the 5 foot thick containment wall, there's another 5 foot thick wall of
steel reinforced concrete called the "dry well wall" in the figure. Inside of this
is the biological shield meant to shield the reactor's radiation. However, this wall
is a 4 foot thickness of leaded concrete with one-inch thick steel liners inside and
outside. Then there's the 4 to 8 inch thick reactor vessel.
So between the crashing airliner and the reactor core are 14 feet of concrete and
6 to 10 inches of steel. In the Sandia tests, a full-sized jet engine traveling at
jet cruising speed can only penetrate two-and-a-half inches of concrete. I'd say
there is a very healthy safety margin.
The safety of nuclear power plants is assured by the laws of physics. The appalling ignorance
of the laws of physics by the anti-nukes is the reason they don't understand why nuclear power
plants are safe.
The anti-nukes postulate all sorts of accidents that could result in harm to the public. However,
when the anti-nukes don't know their physics, and allow water to run uphill, heat to flow from
cold temperatures to hot temperatures, gases to flow from low pressure regions to high pressure
regions, and for momentum to be gained in collisions instead of being conserved, then their
hypothesis are not worth the bandwidth used to promulgate them. Their conjectures are just
baseless fantasiesDid you pass your first year physics class?
PamW